Sliding Window Technique: Everything You Need to Know
Updated on Mar 25, 2025 | 11 min read | 1.1k views
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Updated on Mar 25, 2025 | 11 min read | 1.1k views
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Imagine you are scanning through a long list of numbers, looking for patterns or optimizing results. A naive approach would check every possible subset, making the process slow and inefficient. The Sliding Window Technique offers a smarter way.
This method allows you to analyze contiguous subarrays or substrings efficiently by keeping track of only necessary elements, rather than recalculating from scratch. It significantly reduces time complexity, making it a must-know technique for competitive programming, data structures, and algorithmic optimizations. It plays a crucial role in networking, machine learning, and finance, where real-time analysis is essential.
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Let's break it down and understand how to master this technique for faster, optimized problem-solving.
The Sliding Window Technique is an optimization approach used in problems that involve contiguous sequences of elements. It works by maintaining a fixed or variable-sized window over the dataset and dynamically modifying the result as the window moves forward.
Instead of recomputing the result for every new subset, the technique reuses previously computed values and updates them incrementally. This makes it significantly more efficient than brute-force solutions.
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Problem Statement: Find the maximum sum of a subarray of size k.
Given an array [5, 1, 3, 7, 9, 2, 6, 8, 4, 10] and a window size of 4:
arr = [5, 1, 3, 7, 9, 2, 6, 8, 4, 10]
k = 4
max_sum, window_sum = 0, sum(arr[:k])
for i in range(k, len(arr)):
window_sum += arr[i] - arr[i - k]
max_sum = max(max_sum, window_sum)
print(max_sum) # Output: 24
class SlidingWindow {
public static int maxSumSubarray(int[] arr, int k) {
int maxSum = 0, windowSum = 0;
for (int i = 0; i < k; i++) windowSum += arr[i];
for (int i = k; i < arr.length; i++) {
windowSum += arr[i] - arr[i - k];
maxSum = Math.max(maxSum, windowSum);
}
return maxSum;
}
public static void main(String[] args) {
int[] arr = {5, 1, 3, 7, 9, 2, 6, 8, 4, 10};
System.out.println(maxSumSubarray(arr, 4)); // Output: 24
}
}
function maxSumSubarray(arr, k) {
let maxSum = 0, windowSum = 0;
for (let i = 0; i < k; i++) {
windowSum += arr[i];
}
maxSum = windowSum;
for (let i = k; i < arr.length; i++) {
windowSum += arr[i] - arr[i - k];
maxSum = Math.max(maxSum, windowSum);
}
return maxSum;
}
const arr = [5, 1, 3, 7, 9, 2, 6, 8, 4, 10];
console.log(maxSumSubarray(arr, 4)); // Output: 24
#include <iostream>
#include <vector>
using namespace std;
int maxSumSubarray(vector<int>& arr, int k) {
int maxSum = 0, windowSum = 0;
for (int i = 0; i < k; i++)
windowSum += arr[i];
for (int i = k; i < arr.size(); i++) {
windowSum += arr[i] - arr[i - k];
maxSum = max(maxSum, windowSum);
}
return maxSum;
}
int main() {
vector<int> arr = {5, 1, 3, 7, 9, 2, 6, 8, 4, 10};
cout << maxSumSubarray(arr, 4); // Output: 24
return 0;
}
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Types of Sliding Windows
There are mainly two types of sliding windows:
Here are some real-world case studies related to the sliding window technique:
Here are some of the common mistakes to avoid:
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A naive brute-force approach recalculates results for each new window, leading to O(n²) complexity. The Sliding Window Technique reduces this to O(n) by updating results incrementally.
The Two Pointers technique is useful for problems involving sorted arrays and pair searches, whereas Sliding Window is best for subarray and substring problems.
While Prefix Sum precomputes sums for faster queries, Sliding Window dynamically updates sums, making it better for streaming data or problems requiring real-time updates.
Here are some of the common applications of sliding window technique:
Network Protocols | Used in TCP congestion control for efficient packet handling |
Machine Learning | Applied in real-time data analysis, feature extraction, and anomaly detection. |
Text Processing | Used for pattern matching, plagiarism detection, and substring search. |
Financial Analysis | Helps in stock trend detection, moving averages, and forecasting. |
Here are some of the advantages of sliding window technique:
Here are some of the disadvantages of sliding window technique:
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Common Pitfalls Related to Sliding Window Technique and How to Avoid Them
Here are some of the mistakes or pitfalls:
Here are some of the ways to avoid the above listed pitfalls:
Finding min/max values within a sliding window requires further optimization. A naive approach scans each window (O(n*k) complexity), but a deque allows O(1) extraction, making it highly efficient.
from collections import deque
def max_sliding_window(nums, k):
q = deque()
result = []
for i, num in enumerate(nums):
while q and nums[q[-1]] < num:
q.pop()
q.append(i)
if q[0] == i - k:
q.popleft()
if i >= k - 1:
result.append(nums[q[0]])
return result
Here are some of the problems related to sliding window technique:
Problem Statement: Given an input string, find the length of the longest substring without repeating characters.
Python Solution
def length_of_longest_substring(s):
char_index = {}
left, max_length = 0, 0
for right in range(len(s)):
if s[right] in char_index:
left = max(left, char_index[s[right]] + 1)
char_index[s[right]] = right
max_length = max(max_length, right - left + 1)
return max_length
s = "abcabcbb"
print(length_of_longest_substring(s)) # Output: 3
Problem Statement : Given a string s and a string p, return all the start indices of p's anagrams in s.
Python Solution
from collections import Counter
def find_anagrams(s, p):
result = []
p_count = Counter(p)
s_count = Counter(s[:len(p)])
for i in range(len(p), len(s)):
if s_count == p_count:
result.append(i - len(p))
s_count[s[i]] += 1
s_count[s[i - len(p)]] -= 1
if s_count[s[i - len(p)]] == 0:
del s_count[s[i - len(p)]]
if s_count == p_count:
result.append(len(s) - len(p))
return result
s = "cbaebabacd"
p = "abc"
print(find_anagrams(s, p)) # Output: [0, 6]
Problem Statement: Find the smallest contiguous subarray whose sum is greater than or equal to S.
Python Implementation:
def min_subarray_len(target, nums):
left, curr_sum = 0, 0
min_len = float('inf')
for right in range(len(nums)):
curr_sum += nums[right]
while curr_sum >= target:
min_len = min(min_len, right - left + 1)
curr_sum -= nums[left]
left += 1
return min_len if min_len != float('inf') else 0
print(min_subarray_len(15, [2, 3, 1, 2, 4, 3, 7])) # Output: 2
The Sliding Window Technique is a powerful optimization strategy for solving contiguous sequence problems efficiently. Mastering this technique enhances problem-solving speed, optimizes algorithms, and improves coding efficiency.
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