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DBMS Tutorial: Learn Database …
1. DBMS Tutorial
2. DBMS Architecture
3. Relational Database Management System
4. Data Models in DBMS
5. First Normal Form (1NF)
6. Second Normal Form (2NF)
7. 3rd Normal Form (3NF)
8. BCNF in DBMS
9. Functional Dependency in DBMS
10. Anomalies in DBMS
11. Super Key in DBMS
12. Candidate key DBMS
13. Composite key in DBMS
14. Foreign Key in DBMS
15. Relational Algebra in Database Management
16. Joins in DBMS
17. Indexing In DBMS
18. Transaction in DBMS
19. ACID Properties in DBMS
20. Lock Based Protocol in DBMS
21. Deadlock in DBMS
22. Decomposition in DBMS
Now Reading
23. Aggregation in DBMS
24. Generalization and Specialization in DBMS
25. Data Independence in DBMS
26. Redundancy in DBMS
27. Role-Based Access Control (RBAC)
28. Spatial Databases in DBMS
29. B+ Tree
30. CAP Theorem in DBMS
31. Database Schemas
32. Concurrency Control in DBMS
Decomposition in a Database Management System (DBMS) involves splitting a table into smaller tables to remove duplicate data and enhance data consistency. This makes the database more organized, efficient, and easier to manage. In other words, decomposition is the act of breaking a relation X into X1, X2,……Xn. This method retains dependencies and doesn't lose any data.
Decomposition in DBMS helps remove duplicate data, errors, and inconsistencies from a database by dividing a table into smaller tables.
It is a systematic approach to breaking down tables.
Normalization principles in decomposition are crucial for efficient database design. Here's why:
Decomposition in DBMS refers to dividing a database table into smaller parts or tables. This process replaces one large table with several smaller ones to organize specific sets of data. It's essential for decomposition to be lossless, ensuring that the original data can be accurately reconstructed from the smaller tables. Improper decomposition can lead to data loss and other issues.
Example: In an E-commerce Inventory Management System, the database holds product details. Breaking down this data into separate tables enhances organization and efficiency by reducing redundancy.
Original Table: Inventory
Product_ID | Product_Name | Quantity | Price |
001 | Laptop | 10 | 800 |
002 | Smartphone | 20 | 500 |
003 | Tablet | 15 | 300 |
Sub-table 1: Product_Details
Product_ID | Product_Name |
001 | Laptop |
002 | Smartphone |
003 | Tablet |
Sub-table 2: Inventory_Stock
Product_ID | Quantity | Price |
001 | 10 | 800 |
002 | 20 | 500 |
003 | 15 | 300 |
Decomposition in DBMS mainly comes in two types:
Ensures we can rebuild the original table accurately from the smaller tables.
Requires a common attribute in the smaller tables.
May lose some original data when rebuilding the table.
Can create extra, unnecessary data.
Decomposition in a Database Management System (DBMS) refers to the process of dividing a single table into multiple smaller tables. This is done to enhance data organization, reduce redundancy, and improve database efficiency. To ensure that the database maintains its integrity and reliability post-decomposition, it is essential to adhere to specific properties. Two key properties are:
In summary, for a decomposition to be considered effective and reliable in DBMS, it should be both lossless and should preserve all the functional dependencies present in the original table.
A decomposition is considered lossless if we can reconstruct the original table R by joining the smaller decomposed tables. This method is the preferred choice because it ensures that no information is lost during the decomposition. A lossless join should always produce a result that closely matches the original table.
Key points of Lossless Decomposition:
Now, we decompose this relation into two smaller relations, R1 and R2:
After performing the join operation on R1 and R2, we should get the original Numbers relation:
This demonstrates that the lossless decomposition preserves all the original data when dividing and rejoining the tables.
Example 2:
Let's consider:
Y=(M,N,O)
Y1=(M,N)
Y2=(N,Z)
In this example, the relation Y has attributes M,N, and O. After decomposition, we get two separate relations, Y1 and Y2, each with two attributes. The common attribute between Y1 and Y2 is N.It's important to note that the values in the N column must be unique. If there are duplicate values, a lossless-join decomposition would not be possible.
Example 3:
Consider a table with the relation X that contains the following raw data:
This relation can be decomposed into the following sub-relations, X1 and X2:
Let's check the first condition to determine if the decomposition is a lossless-join decomposition. In this case, the union of the sub-relations X1 and X2 should yield the same result as the original relation X.
X1∩X2=X
The resulting table is:
As the resulting table is identical to the original relation X, this decomposition can be considered a lossless join decomposition in DBMS.
Consider a relational schema Y with attributes A,B,C, and D, and the following functional dependencies:
A→B,B→C,C→D,D→A
If the relation Y is decomposed into the following smaller relations:
R1(A,B),
R2(B,C),
R3(C,D)
The decomposition would:
A. Result in a lossless join but is not dependency preserving.
B. Result in a lossless join and is dependency preserving.
C. Not result in a lossless join and is not dependency preserving.
D. Not result in a lossless join but is dependency preserving.
Answer with Explanation:B. Result in a lossless join and is dependency preserving.
Explanation:
To determine if the decomposition is lossless and dependency preserving:
Lossless Join:
The intersection of the decomposed relations should include a superkey of the original relation.
For R1 and R2, the intersection is B, and for R2 and R3, the intersection is C. Since both B and C are attributes that can derive other attributes, the intersection of all decomposed relations will give us all the attributes of Y.
Dependency Preservation:
All the functional dependencies in the original relation should be represented in the decomposed relations.
The given decomposition does represent all the functional dependencies from the original relation: R1 represents A→B R2 represents B→C R3 represents C→DFurthermore, the dependency D→A is indirectly preserved through the decomposition.
Therefore, the correct answer is B. Result in a lossless join and is dependency preserving.
Analyzing Lossy Decomposition
Lossy decomposition occurs when a single relation is divided into multiple relational schemas in a way that retrieving the original relation results in a loss of information. In other words, some data from the original relation may not be recoverable from the decomposed relations, leading to a loss of information.
Example:
Consider a relation X that is decomposed into n sub-relations: {X1,X2,X3,…,Xn}. If the natural join of these sub-relations does not yield the original relation X, it is classified as a lossy decomposition in DBMS.
However, it may not retain all the original data, leading to potential data loss.
Unlike lossless decomposition, lossy decomposition does not always maintain all the original functional dependencies in the smaller tables.
Some data from the original relation may not be included or recoverable in the decomposed smaller tables.
Careless decomposition, also known as lossy join decomposition, introduces extraneous tuples when performing the natural join of the sub-relations. These additional tuples can make it challenging to distinguish the original tuples from the decomposed relations.
Example 1:Let us consider the following table which has employee information:
Now let us decompose this table into two sub tables:
If we attempt to join both of the tables mentioned above, we won't be able to do so because the attribute Emp_ID is not included in the <Dept_Details> table.
Thus, this decomposition is an example of lossy decomposition.
Example 2:Let's consider the relation Y with attributes A,B,C.
Assuming this relation Y gets decomposed into Y1(A,C) and Y2(B,C) sub-relations, these two sub-relations would look like:
Let's check if this decomposition is lossy. For a lossy decomposition, we should have:
Y1⋈Y2⊇Y
Now, let's perform the natural join ⋈ of these sub-relations Y1 and Y2. The resulting table is:
The resulting relation is not identical to the original relation Y and contains extraneous tuples.
Thus, Y1⋈Y2 ⊇Y.
In conclusion, the decomposition mentioned here is a lossy decomposition.
Consider a relation S with attributes X,Y,Z,W:
Assume that this relation S is decomposed into two sub-relations S1(X,Y,Z) and S2(Y,W) as follows:
Determine whether the decomposition is:
A. Lossless Decomposition
B. Lossy Decomposition
C. Cannot be determined
D. Both A and B
Answer with Explanation:
The decomposition is considered lossy if the natural join of the decomposed relations does not result in the original relation.
Now, let's perform the natural join ⋈ of S1 and S2:
The resulting relation is not identical to the original relation S and contains only two rows, making this a lossy decomposition.
Thus, the correct answer is:
B. Lossy Decomposition
2. Check whether the given decomposition is a lossy join decomposition.
Original Relation:
Decomposition:
Is this decomposition:
A. Lossless Decomposition
B. Lossy Decomposition
C. Cannot be determined
D. Both A and B
Answer with Explanation:
Upon trying to join the two tables mentioned above, we won't be able to do it since the attribute ID is not present in the Location_Info table.
Thus, this relation mentioned here is a lossy decomposition.
Answer: Lossy Decomposition.
Properties of Decomposition
In summary, while decomposition has benefits like better data organization, it also has challenges that need careful handling to keep the database running smoothly.
When creating and refining a database, it's important to organize it properly to keep data accurate and avoid unnecessary repetition. To achieve this, we use advanced techniques known as Boyce-Codd Normal Form (BCNF) and Fourth Normal Form (4NF). Let's break down these concepts to make them easier to understand:
BCNF is a method to organize data in a database to minimize redundancy and maintain data consistency. The main rule for BCNF is that every piece of data (non-key attribute) in a table should only depend on the primary key.
Example:
Suppose we have a table called Student_Course:
Student_Course (Student_ID, Course_ID, Course_Name, Instructor)
To apply BCNF:
Student_Course_Info (Student_ID, Course_ID)
Course_Details (Course_ID, Course_Name, Instructor)
Why is BCNF useful?
It ensures consistent data throughout the database and simplifies data updates without impacting various sections of the database.
4NF builds upon BCNF by specifically targeting the elimination of multi-valued dependencies in the data; thus, a table in BCNF should be free of any multi-valued dependencies.
Example:
Consider the Employee_Project table:
Employee_Project (Employee_ID, Project_ID, Employee_Name, Project_Name)
In this table, Employee_Name is dependent on Project_ID, which is a multi-valued dependency.
To reach 4NF:
Employee_Project_Info (Employee_ID, Project_ID)
Employee_Details (Employee_ID, Employee_Name)
Project_Details (Project_ID, Project_Name)
Why is 4NF useful?
It helps minimize data repetition by separating multi-valued attributes and ensures that the data remains accurate and free from anomalies.
Advanced decomposition methods such as BCNF and 4NF are essential for efficient database structure. These techniques manage complex data structures and dependencies, improving data integrity, minimizing redundancy, and streamlining database maintenance.
Decomposition in DBMS is a crucial process that involves splitting down a single relation into multiple smaller relations to eliminate redundancy and improve data integrity.
There are two main types of decompositions:
Ensures we can rebuild the original table accurately from the smaller tables.
Requires a common attribute in the smaller tables.
May lose some original data when rebuilding the table.
Can create extra, unnecessary data.
Choosing between these types depends on the specific needs of the database. Proper use of decomposition is key for an efficient database design.
1. What is non loss decomposition in DBMS?
Non-loss decomposition is a method in DBMS where the original table can be fully reconstructed from the smaller tables without losing any data.
2. What is redundancy in DBMS?
In DBMS, redundancy means having duplicate data in the database. This happens when the exact same information is stored in more than one place or table. Redundancy can happen due to reasons like inefficient database design or not following normalization principles.
3. What are the problems related to decomposition Explain?
Already mentioned under the heading disadvantage of decomposition in DBMS
4. What is decompose in SQL?
Decomposition in SQL means breaking down a single table into smaller tables to reduce redundancy and improve data organization.
5. What is decomposition and its type in DBMS?
Already mentioned under the heading What is decomposition and type in DBMS
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